RE: [Mathematics] Official Help Thread 04-26-2015, 07:20 AM
#11
[Mathematics] Official Help Thread filter_list | |
RE: [Mathematics] Official Help Thread 04-26-2015, 07:27 AM
#12
(04-26-2015, 07:20 AM)Losi Wrote: Lmao. You gotta start somewhere.
I bet we got some freshies on SL anyways.
In my opinion, geometry is the easiest math. SOCAHTOA is probably the hardest part, in my opinion. Once you get past that, everything should be pretty easy. In my opinion.
![[Image: 8536321abf.jpg]](http://puu.sh/kt29S/8536321abf.jpg)
[STAFF DETERMINED SIGNATURE AS LEWD]
JDM>USDM
RE: [Mathematics] Official Help Thread 04-26-2015, 10:05 AM
#13
(04-26-2015, 03:06 AM)ねこまっしぐら Wrote: Yal talkin' geometry, that's first year of high school level math.
My first year of high schools math lessons were mostly filled with sleeping and just remembering whatever fuck I had to do for the tests. (y)
![[Image: tumblr_noac9s6rgw1tvnnaxo1_500.gif]](https://33.media.tumblr.com/95c52b25dceea2bedb89888221404c11/tumblr_noac9s6rgw1tvnnaxo1_500.gif)
Tik Tak~! Time is up~!
RE: [Mathematics] Official Help Thread 04-26-2015, 03:39 PM
#14
Could this thread and this one be stickied temporarily? @"Dismas" @"roger_smith"
RE: [Mathematics] Official Help Thread 04-26-2015, 03:43 PM
#15
stickied for 30 days
---
Click here to get started with Linux!
If I helped you, please +rep me, apparently we've started over on Rep and I'd like to break 100 again...
Click here to get started with Linux!
If I helped you, please +rep me, apparently we've started over on Rep and I'd like to break 100 again...
Inori Wrote: got clickbaited by roger
RE: [Mathematics] Official Help Thread 10-19-2015, 12:09 AM
#17
ITT: highschool students who took a pre-calculus class and now think they're Leonhard Euler
RE: [Mathematics] Official Help Thread 01-11-2016, 02:05 AM
#19
I can barely tell if this thread is genuine, but I'm looking for some core/mechanics help with something I can't find on the interwebs (Probably not looking hard enough not gonna lie.
So lets say I have a function that I can graph Euclid style. And I take the integral of the graph between the points a and b.
Is there a way such that I can find the X (call it m)coordinate where:
And the Y (call it n)coordinate where:
So lets say I have a function that I can graph Euclid style. And I take the integral of the graph between the points a and b.
Is there a way such that I can find the X (call it m)coordinate where:
Spoiler:
Spoiler:
RE: [Mathematics] Official Help Thread 05-24-2016, 10:02 PM
#20
(01-11-2016, 02:05 AM)Rick Wrote: I can barely tell if this thread is genuine, but I'm looking for some core/mechanics help with something I can't find on the interwebs (Probably not looking hard enough not gonna lie.
So lets say I have a function that I can graph Euclid style. And I take the integral of the graph between the points a and b.
Is there a way such that I can find the X (call it m)coordinate where:
And the Y (call it n)coordinate where: Spoiler:
Spoiler:
Sorry, was away.
For your first question, assuming the area under the graph between x=b and x=m is equal to the area under the graph between x=m and x=a, and assuming you know the values of a and b, you could actually find the integral of y=f(x), and then substitute in the values and equate them.
i.e.
let g(x) be the function of the integral of f(x)
thus g(b) - g(m) = g(m) - g(a)
Then rearrange and solve for m. If you come out with a polynomial, you can find the discriminant and check if it's more than or equal to 0. If not, there's no point solving for m since there's no (real) solutions.
As for your second question, I actually don't know what you mean. Maybe clarify it a little?
(This post was last modified: 05-24-2016, 10:03 PM by Eclipse.)
Users browsing this thread: 1 Guest(s)