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RE: Homework #21
Also pro-tip

Always keep it in fractions, when you get into next year teachers don't like decimals at all, and it's easier when you get into more complicated stuff than dealing with decimals.

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RE: Homework #22
(03-22-2013, 01:39 AM)Flashdrive Wrote: Also pro-tip

Always keep it in fractions, when you get into next year teachers don't like decimals at all, and it's easier when you get into more complicated stuff than dealing with decimals.

Yea, but this year, our math teacher's been telling us to keep it in decimals. So the answer is basically y= 3.50 right?

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RE: Homework #23
(03-22-2013, 01:42 AM)ABC Wrote: Yea, but this year, our math teacher's been telling us to keep it in decimals. So the answer is basically y= 3.50 right?

Yeah that's the answer, although they just say that because they think it's more confusing. I'd practice with fractions.

Cause once you start doing things like 3 x 3 equations, or 4 x 4 equations I like fractions better.

What you guys are doing is a 2 x 2 equation ( 2 unknowns "x, and y" )

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RE: Homework #24
(03-22-2013, 01:44 AM)Flashdrive Wrote: Yeah that's the answer, although they just say that because they think it's more confusing. I'd practice with fractions.

Cause once you start doing things like 3 x 3 equations, or 4 x 4 equations I like fractions better.

What you guys are doing is a 2 x 2 equation ( 2 unknowns "x, and y" )

So basically 3x3 and 4x4s are more complex equations, but not run-ons?

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RE: Homework #25
(03-22-2013, 01:46 AM)ABC Wrote: So basically 3x3 and 4x4s are more complex equations, but not run-ons?

A 3 x 3 equation is like.

Code:
2x + 3z = 2y + 4
3z + 2y = 3x
x + z + y = 4

Than you'd use elimination method or substitution to solve for it (or matrices which I don't think you've learned) than you have to solve for x, y, and z.

Although don't worry about it it just like the same thing except for you'd solve it differently it takes up like 2/3rds of the page.

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RE: Homework #26
(03-22-2013, 01:51 AM)Flashdrive Wrote: A 3 x 3 equation is like.

Code:
2x + 3z = 2y + 4
3z + 2y = 3x
x + z + y = 4

Than you'd use elimination method or substitution to solve for it (or matrices which I don't think you've learned) than you have to solve for x, y, and z.

Although don't worry about it it just like the same thing except for you'd solve it differently it takes up like 2/3rds of the page.

That seems rather simple, it's the exact same thing, just a different number of variables. And no, we haven't learned Matrices yet).

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RE: Homework #27
Wow your math is so easy. I miss those days.

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RE: Homework #28
(03-22-2013, 02:02 AM)Jinx Wrote: Wow your math is so easy. I miss those days.

It's rather simple, but shit, there is only TWO question I can't figure out. Butt fuck it, my teacher will probably accept it anyways.

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