[King_Uv_All_Darkness]

ok brandon i understand that but i bet if half of them dont do it she might give it to the ppl who didnt do it so just play it safe and double wrap this metephorical condom before you stick it in. @Flashdrive it shows me x + 2 + 1 = 3x
x + 3 = 3x
3 = 2x
x= 3/2 or 1 1/2

[Feat]

So, you have the answer Daniel. You're supposed to answer the questions on 142.

/thread

[King_Uv_All_Darkness]

where did you get that there are no questions on 142

[Feat]

My bad, 141, you use the answer/equations on page 140.

[King_Uv_All_Darkness]

i know thats where im getting these equations from

[Flashdrive]

ok brandon i understand that but i bet if half of them dont do it she might give it to the ppl who didnt do it so just play it safe and double wrap this metephorical condom before you stick it in. @Flashdrive it shows me x + 2 + 1 = 3x
x + 3 = 3x
3 = 2x
x= 3/2 or 1 1/2

So what's the question for you it answered it already?

If you have the equations

Code:

y = x + 2
y + 1 = 3x
(x + 2) + 1 = 3x

And you have to sub the value "y" in which equals "x + 2"

You would get one of the equations in this case "y + 1 = 3x"
You know what "y" is because it tells you "y = x + 2"
So then you sub the "y" value into the equation which makes:

x + 2 + 1 = 3x
(x + 2) is your "y" after you sub in for it.

Once you have that you simply combine like terms on the left side which makes it.

x + 3 = 3x

so once you have that you need to get "x" alone so you subtract the "x" off of the left side and bring it over to the right side so you subtract it and write it like this.

3 = 3x - x
( 3x really means "x x x" so if you take an "x" away you're left with two x's which is put as "2x" )

3 = 2x

Once you have that you need to get "x" alone and sense you have "2x" which is really like saying " X times 2 " you have to do the opposite of multiplication which is division so you divide both sides by "2" to get "x" alone making it.

3/2 = x

And if you wanted to you can also write it as.

1 1/2 = x

they're the same things one is mixed fractions, and one is improper.

[King_Uv_All_Darkness]

yes but they want me to substitute x in the equation y = x + 2 to find y

[Feat]

yes but they want me to substitute x in the equation y = x + 2 to find y

So, you're gonna substitute using 1.50 since that's the solution to X

[Flashdrive]

yes but they want me to substitute x in the equation y = x + 2 to find y

Alright so now that we know

" x = 3/2 "

we can than sub "x" into the equation.

Code:

y = x + 2

it would be.

y = 3/2 + 2

Sense we have to add fractions we need to make 2 into a fraction, and sense 2 is equal to 2/1 we need to make the denominator of "1" into a 2 so we multiply the top and the bottom by "2" making it 4/2 so it becomes.

y = 3/2 + 4/2

Which than is.

y = 7/2

Bam.

[King_Uv_All_Darkness]

; P

Alright so now that we know

" x = 3/2 "

we can than sub "x" into the equation.

Code:

y = x + 2

it would be.

y = 3/2 + 2

Sense we have to add fractions we need to make 2 into a fraction, and sense 2 is equal to 2/1 we need to make the denominator of "1" into a 2 so we multiply the top and the bottom by "2" making it 4/2 so it becomes.

y = 3/2 + 4/2

Which than is.

y = 7/2

Bam.

thanks man appreciate it. ; P