[Challenge] Hello, Creativity!

Eclipse · 08-25-2015, 10:25 PM

Code:
import requests as r
import random

pi = r.get('http://newton.ex.ac.uk/research/qsystems/collabs/pi/pi6.txt').text
pi = str("".join(pi.split()))

splitted = []

prev = 0
while True:
    n = random.randint(1,3)
    splitted.append(pi[prev:prev+n])
    prev = prev + n
    if prev >= len(pi)-1:
        break

splitted = splitted[2:]

completed = []
#Hello, Creativity!

for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "H":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "e":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "l":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "l":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "o":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == ",":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == " ":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "C":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "r":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "e":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "a":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "t":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "i":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "v":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "i":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "t":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "y":
            completed.append(chr(dec))
            break
for dec in splitted:
    dec = int(dec)
    if dec < 256:
        if chr(dec) == "!":
            completed.append(chr(dec))
            break

strcompleted = ''

for char in completed:
    strcompleted += char

print strcompleted

3,030 bytes

1) Retrieve Pi to a million digits and convert to string
2) Split string every n characters where n is a random integer between 1 and 3
3) Iterate through split string for each character of target string, convert the integer to its ascii chr()
4) Check if result is same as target character
5) If yes, append the chr() of the integer to a list.
6) print

[Challenge] Hello, Creativity!
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