[Tiszy]

Your last picture is wrong. If you add a piece of copper in at 7, that would take bulbs "B" and "C" out of the mix. You're removing the parallel circuit from the equation by doing so. If the electricity follows the path of least resistance, it would flow through bulb 1 and 2, then go through the now-replaced bulb 7 that is instead a jumper wire. BECAUSE OF THIS, THERE MAY BE MINIMAL VOLTAGE AT THE REMAINING LEGS OF THE PARALLEL CIRCUIT, HOWEVER THE BULBS WILL NOT LIGHT, BECAUSE THERE ISN'T ENOUGH VOLTAGE TO LIGHT THEM.

Remember, voltage = electrical pressure. The lights require a certain amount of "pressure" to work, kinda like a garden hose or an air tool. If you don't have enough pressure, the air tool won't run, the hose won't spray.

I took automotive electrical and held electrical certifications for a while. We did nearly this exact lab in my class. The lights didn't light.

Yes they will still light if you have the wire at the end, because all the way its 12V/6V since its both series and parallell...

And thats weird, it should light, I think I'll setup this myself tomorrow