[Tiszy]

But bulbs 1 and 2 would use up the voltage, and have an amperage draw to them, so it wouldn't be like a direct ground fault.

Let say the battery is 12V

Bulb 1 and 2 would have 4V each, and the other bubs would either have 2V or 4V(2V for 3,4 and 4,5, and 4V for 7)

Since the cobber which I understood would be changed out with bulb 7, means it will have 4V.

In this case, I do not know the I or W, so I can't calculate the power usage here.
But my conclusion is that either the cobber will melt slowly or the battery will explode/melt.

It will still be direct between the pole, + and - with 4V, but I don't know how much I(A) it will go through this system, since I do not know the resistance of the bulbs...

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But bulbs 1 and 2 would use up the voltage, and have an amperage draw to them, so it wouldn't be like a direct ground fault.

Also no, bulb 1 and 2 won't use all the voltage, its equally spread out, but the last one is 5 bulbs kinda in a parallel(idk what you call it in english) so it will also equally be spread out with bulb 1 and 2

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But bulbs 1 and 2 would use up the voltage, and have an amperage draw to them, so it wouldn't be like a direct ground fault.

Also no, bulb 1 and 2 won't use all the voltage, its equally spread out, but the last one is 5 bulbs kinda in a parallel(idk what you call it in english) so it will also equally be spread out with bulb 1 and 2