[Inori]

I have no idea what to call this program but it's a game/problem my math teacher used to give us last year. The concept: You need to find a 4 digit number using the numbers 0-9 in the allotted number of tries. If you get one right, you get one more try, get it wrong, you lose one.

It's not my best program and I made it because I got bored in BTT but hey, enjoy!

Code:

#by Touka, ©2015 actions = (0..9).to_a @sequence = [] 4.times do |key| key = actions.sample @sequence << key end @fails_left = gets.to_i @correct_a = 0 @correct_r = 0 @a = " " @b = " " @c = " " @d = " " def sel system "cls" puts """ __________________________________ / ___ ___ ___ ___ \\ | | | | | | | | | | | | #{@a} | | #{@b} | | #{@c} | | #{@d} | | | |___| |___| |___| |___| | \\__________________________________/ Tries left: #{@fails_left} Enter guess (x x x x):""" guess = gets.chomp guess = guess.split(" ") guess = guess.map(&:to_i) @correct_a_prev = @correct_a case guess[0] when @sequence[0] @correct_a += 1 @a = "#" when @sequence[1] @correct_r += 1 when @sequence[2] @correct_r += 1 when @sequence[3] @correct_r += 1 end case guess[1] when @sequence[0] @correct_r += 1 when @sequence[1] @correct_a += 1 @b = "#" when @sequence[2] @correct_r += 1 when @sequence[3] @correct_r += 1 end case guess[2] when @sequence[0] @correct_r += 1 when @sequence[1] @correct_r += 1 when @sequence[2] @correct_a += 1 @c = "#" when @sequence[3] @correct_r += 1 end case guess[3] when @sequence[0] @correct_r += 1 when @sequence[1] @correct_r += 1 when @sequence[2] @correct_r += 1 when @sequence[3] @correct_a += 1 @d = "#" end if @correct_a_prev - @correct_a == 0 @fails_left -= 1 else hi = " " end if @fails_left == 0 system "cls" puts "you've died. :3" sleep else sel end end sel