Sinisterly
tic tac toe - Printable Version

+- Sinisterly (https://sinister.ly)
+-- Forum: Coding (https://sinister.ly/Forum-Coding)
+--- Forum: Java, JVM, & JRE (https://sinister.ly/Forum-Java-JVM-JRE)
+--- Thread: tic tac toe (/Thread-tic-tac-toe)

tic tac toe - blackeagle - 11-12-2013

few days ago i saw @Ex094 working on making a tic tac toe game in c i found it interesting and it will be a good challenge for me so i started working on that project !!
as every1 helped me on my first project rock scissors paper game and gave me feedbacks to make it better i wish you could do the same here !!

first i'll share with you my code i'm stuck somewhere couldn't figure out a way to do it so you guys could start by helping me solving this problem then giving me advices on how to make my code better!!

Spoiler:
Code:
package tictactoe;
import java.util.Random;
import java.util.Scanner;
public class TicTacToe {

    public static void viewBoard(char board[]){
System.out.println("|"+board[0]+"|"+board[1]+"|"+board[2]+"|");
System.out.println("|"+board[3]+"|"+board[4]+"|"+board[5]+"|");
System.out.println("|"+board[6]+"|"+board[7]+"|"+board[8]+"|");
}
public static int whoStart(){
    int turn;
    int rand=new Random().nextInt(2);
    
    if(rand==1){return turn=1;}
    return turn=2;

}
public static int makeMove(char board[],int turn,int box){
    if(turn%2==0){board[box]='o';}
    else{board[box]='x';
}
    return box;
}
public static boolean isValidMove(char board[],int box){
    if ((board[box]=='x')||(board[box]=='o')){return true;
        
    }
    return false;
    
}

public static boolean checkWin(char board[]){
    //first horizontal line
    if(((board[0]==board[1])&&(board[1]==board[2])&&(board[2]=='o'))||
    ((board[0]==board[1])&&(board[1]==board[2])&&(board[2]=='x'))||
    //seconde horizontal line
    ((board[3]==board[4])&&(board[4]==board[5])&&(board[5]=='o'))||
    ((board[3]==board[4])&&(board[4]==board[5])&&(board[5]=='x'))||
    //third horizontal line
    ((board[6]==board[7])&&(board[7]==board[8])&&(board[8]=='o'))||
    ((board[6]==board[7])&&(board[7]==board[8])&&(board[8]=='x'))||
    //first vertical line
    ((board[0]==board[3])&&(board[3]==board[6])&&(board[6]=='o'))||
   ((board[0]==board[3])&&(board[3]==board[6])&&(board[6]=='x'))||
    //seconde vertical line
    ((board[1]==board[4])&&(board[4]==board[7])&&(board[7]=='o'))||
   ((board[1]==board[4])&&(board[4]==board[7])&&(board[7]=='x'))||
    //third vertical line
  ((board[2]==board[5])&&(board[5]==board[8])&&(board[8]=='o'))||
    ((board[2]==board[5])&&(board[5]==board[8])&&(board[8]=='x'))||
    //first diagonal line
     ((board[0]==board[4])&&(board[4]==board[8])&&(board[8]=='o'))||
     ((board[0]==board[4])&&(board[4]==board[8])&&(board[8]=='x'))||
     //seconde diagonal line
     ((board[6]==board[4])&&(board[4]==board[2])&&(board[2]=='o')))
    
    {return true;}
    return false;
}
    public static void main(String[] args) {
Scanner in=new Scanner(System.in);
char board[]={'0','1','2','3','4','5','6','7','8'};
        System.out.println("enter player 1 name");
String player1Name=in.nextLine();
System.out.println("enter player 2 name");
String player2Name=in.nextLine();
viewBoard(board);
System.out.println(whoStart());
int turn=whoStart();int counter=0;
  do{      System.out.println("choose box number");
    int box=in.nextInt();
    while(isValidMove(board,box)){
System.out.println("choose another box");
box=in.nextInt();}
    makeMove(board,turn,box);
    viewBoard(board);
    turn++;
    counter++;
  }
  while ((counter<9)&&(checkWin(board)==false));
          }

ok so as you can see in my main it keeps asking to choose a box until the counter is equal or bigger then 9 or we have a winner!!
what i want to do is after the do while is over if we have a winner i wanted to say the winner is player 1 if player 1 won or the winner is player 2 if player 2 won and finally it's a tie if no1 won !!
can u give me ideas on how to do it ?
thx in advance for the help Smile

RE: tic tac toe - Ex094 - 11-12-2013

I think the CheckWin part can be done in a more clear way using Java, Do some searches on Google and I'm sure you'll find it.

RE: tic tac toe - blackeagle - 11-12-2013

i'll work on this later but first i need a little help to be able to finish my code !!

RE: tic tac toe - Deque - 11-13-2013

Quote:what i want to do is after the do while is over if we have a winner i wanted to say the winner is player 1 if player 1 won or the winner is player 2 if player 2 won and finally it's a tie if no1 won !!
can u give me ideas on how to do it ?

Instead of returning a boolean let the checkWin return who won.
Look into Enums: http://docs.oracle.com/javase/tutorial/java/javaOO/enum.html
Then create an enum type that has the values: PLAYER1, PLAYER2, NO_WINNER
Then you will say something like:

Code:
while ((counter < 9) && (checkWin(board) == NO_WINNER));
if (counter >= 9) {
  //tie
} else if (checkWin(board) == PLAYER1) {
  //player 1 is winner
} else {
  //player 2 is winner
}