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+---- Thread: Eletrical Circuit Question (/Thread-Eletrical-Circuit-Question)
RE: Eletrical Circuit Question - HTH - 05-07-2015
Unless the copper you are putting in to replace bulb 7 is an ideal short (0 ohms, and impossible thanks to internal resistance) then all bulbs will still be receiving power. The lower the resistance of this short the less current the other parallel branches will see (it may not even be enough for the bulbs to light) but it WILL spread out according to Current Dividing.
For the record the current in a given branch is found by It(Rt/Rb+Rt)
Where It = Total Current, and Rb and Rt are the Resistance of the branch and total resistance of all the branches respectively.
So even if the other bulbs dont light up there will still be power across them.
Feel free to check this using a multimeter
RE: Eletrical Circuit Question - Inori - 05-07-2015
(05-07-2015, 04:57 AM)Tarew Wrote: I'm also in 9th grade public school
If you have a tech department, they can probably hook you up.
Or am I being baited? -suspicion intensifies-
RE: Eletrical Circuit Question - roger_smith - 05-08-2015
(05-07-2015, 05:31 AM)HTH Wrote: Unless the copper you are putting in to replace bulb 7 is an ideal short (0 ohms, and impossible thanks to internal resistance) then all bulbs will still be receiving power. The lower the resistance of this short the less current the other parallel branches will see (it may not even be enough for the bulbs to light) but it WILL spread out according to Current Dividing.
For the record the current in a given branch is found by It(Rt/Rb+Rt)
Where It = Total Current, and Rb and Rt are the Resistance of the branch and total resistance of all the branches respectively.
So even if the other bulbs dont light up there will still be power across them.
Feel free to check this using a multimeter
We're likely talking mV levels of voltage at this point. The bulbs will have a higher resistance than a copper wire replacing the bulb, and thus will not illuminate.
RE: Eletrical Circuit Question - HTH - 05-08-2015
You're right, in that it will be a small amount of power in any of the branches, and with a sane copper branch/power level/bulb choice the bulb's won't illuminate..but, and thsi is something I have to tell all my students...
Electricity Follows all Paths given to it, you cannot EVER assume that it follows only a given path. (Even with a diode you should consider what happens if it fries) That's how you break things, and with larger power levels, yourself.
The electricity left in those other branches would be enough to illuminate some low-wattage LEDs or fry sensitive electronics. Basically don't assume that electricity JUST follows the path of least resisitance, if that was true, the original circuit with the #7 lamp would ONLY illuminate that #7 lamp anyway!
RE: Eletrical Circuit Question - roger_smith - 05-09-2015
(05-08-2015, 07:54 PM)HTH Wrote: You're right, in that it will be a small amount of power in any of the branches, and with a sane copper branch/power level/bulb choice the bulb's won't illuminate..but, and thsi is something I have to tell all my students...
Electricity Follows all Paths given to it, you cannot EVER assume that it follows only a given path. (Even with a diode you should consider what happens if it fries) That's how you break things, and with larger power levels, yourself.
The electricity left in those other branches would be enough to illuminate some low-wattage LEDs or fry sensitive electronics. Basically don't assume that electricity JUST follows the path of least resisitance, if that was true, the original circuit with the #7 lamp would ONLY illuminate that #7 lamp anyway!
I disagree with that statement, but see the point you're trying to make.
However, like I said before, you're talking about such minute voltage with bulb 7 bridged, it's effectively nothing.
I guess I'll scrape up some munnies and build this circuit to test the various theories on how it will function.
RE: Eletrical Circuit Question - Nyx - 05-09-2015
(05-08-2015, 07:54 PM)HTH Wrote: You're right, in that it will be a small amount of power in any of the branches, and with a sane copper branch/power level/bulb choice the bulb's won't illuminate..but, and thsi is something I have to tell all my students...
Electricity Follows all Paths given to it, you cannot EVER assume that it follows only a given path. (Even with a diode you should consider what happens if it fries) That's how you break things, and with larger power levels, yourself.
The electricity left in those other branches would be enough to illuminate some low-wattage LEDs or fry sensitive electronics. Basically don't assume that electricity JUST follows the path of least resisitance, if that was true, the original circuit with the #7 lamp would ONLY illuminate that #7 lamp anyway!
The bulbs in this circuit are the tiny little 1.5V bulbs.
RE: Eletrical Circuit Question - capitanPatel - 11-26-2019
energy saving is a really important thing nowadays taking into consideration the ongoing climate change and the technology of the last century does not fit in the picture of saving our planet or making a significant needed change in regards of that and what do we do instead we use the same run-down utilities that pollute and consume more let's take in perspective the same old light bulbs just changing them for new led ones not only we stop polluting planet with wolfram and cooper but we also receive a way lower bill for energy consumption and a brighter light all around the house win-win situation in my opinion and plus if you do care about saving and polluting less and you live in Australia address to professionals like spark innovations with a 24/7 working line that will always advise you and take care of your needs. Let's make our planet great again let's make a change let's save mother nature