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[Mathematics] Official Help Thread - Printable Version

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RE: [Mathematics] Official Help Thread - Losi - 04-26-2015

(04-26-2015, 03:06 AM)ねこまっしぐら Wrote: Yal talkin' geometry, that's first year of high school level math.

Lmao. You gotta start somewhere.

I bet we got some freshies on SL anyways.


RE: [Mathematics] Official Help Thread - ねこまっしぐら - 04-26-2015

(04-26-2015, 07:20 AM)Losi Wrote: Lmao. You gotta start somewhere.

I bet we got some freshies on SL anyways.

In my opinion, geometry is the easiest math. SOCAHTOA is probably the hardest part, in my opinion. Once you get past that, everything should be pretty easy. In my opinion.


RE: [Mathematics] Official Help Thread - Jolly - 04-26-2015

(04-26-2015, 03:06 AM)ねこまっしぐら Wrote: Yal talkin' geometry, that's first year of high school level math.

My first year of high schools math lessons were mostly filled with sleeping and just remembering whatever fuck I had to do for the tests. (y)


RE: [Mathematics] Official Help Thread - Eclipse - 04-26-2015

Could this thread and this one be stickied temporarily? @"Dismas" @"roger_smith"


RE: [Mathematics] Official Help Thread - roger_smith - 04-26-2015

stickied for 30 days


RE: [Mathematics] Official Help Thread - Eclipse - 10-18-2015

Bumping this.


RE: [Mathematics] Official Help Thread - username1 - 10-19-2015

ITT: highschool students who took a pre-calculus class and now think they're Leonhard Euler


RE: [Mathematics] Official Help Thread - Eclipse - 10-19-2015

(10-19-2015, 12:09 AM)username1 Wrote: ITT: highschool students who took a pre-calculus class and now think they're Leonhard Euler

[Image: 87C1W7B.jpg]


RE: [Mathematics] Official Help Thread - Rick - 01-11-2016

I can barely tell if this thread is genuine, but I'm looking for some core/mechanics help with something I can't find on the interwebs (Probably not looking hard enough not gonna lie.

So lets say I have a function that I can graph Euclid style. And I take the integral of the graph between the points a and b.

Is there a way such that I can find the X (call it m)coordinate where:
And the Y (call it n)coordinate where:
Spoiler:
https://latex.codecogs.com/gif.latex?%5Cleft%20%28%20%5Cint_%7Ba%7D%5E%7Bb%7Df%28x%29%20%5Cright%20%29%20-%5Cint_%7Ba%7D%5E%7Bb%7Dn%20%3D%20P
Where P is the definite integral of the graph under "y = n"
(I have no idea how to even express it)



RE: [Mathematics] Official Help Thread - Eclipse - 05-24-2016

(01-11-2016, 02:05 AM)Rick Wrote: I can barely tell if this thread is genuine, but I'm looking for some core/mechanics help with something I can't find on the interwebs (Probably not looking hard enough not gonna lie.

So lets say I have a function that I can graph Euclid style. And I take the integral of the graph between the points a and b.

Is there a way such that I can find the X (call it m)coordinate where:
And the Y (call it n)coordinate where:
Spoiler:
https://latex.codecogs.com/gif.latex?%5Cleft%20%28%20%5Cint_%7Ba%7D%5E%7Bb%7Df%28x%29%20%5Cright%20%29%20-%5Cint_%7Ba%7D%5E%7Bb%7Dn%20%3D%20P
Where P is the definite integral of the graph under "y = n"
(I have no idea how to even express it)

Sorry, was away.

For your first question, assuming the area under the graph between x=b and x=m is equal to the area under the graph between x=m and x=a, and assuming you know the values of a and b, you could actually find the integral of y=f(x), and then substitute in the values and equate them.

i.e.
let g(x) be the function of the integral of f(x)
thus g(b) - g(m) = g(m) - g(a)

Then rearrange and solve for m. If you come out with a polynomial, you can find the discriminant and check if it's more than or equal to 0. If not, there's no point solving for m since there's no (real) solutions.

As for your second question, I actually don't know what you mean. Maybe clarify it a little?