Conversion of IP-s in bits 04-03-2012, 09:04 AM
#1
Conversion of IP-s in bits
Greetings.
In this tutorial will tell you that you to convert an ip, in bits.
As the dim IP Verssion 4, we use is 32 bitsh, as consists of 4 octets with 8 bits, 8 x 4 = 32 bits.
Let's continue with the tutorial, we get 1 IP, 192.168.24.8 for example, will now start with converting the bits.
First octet is below 192 now denote by
128, 64, 32, 16, 8, 4, 2, 1
--------------------------------
FIRST octet (192)
1.Tash 128 to 192, goes to her and mark a 1 1 (192-128 = 64) ie residue 64
2.Tash 64 runs in her first 64 (remainder of 192-168) and remark the one, now 64-64 = 0, ie remaining 0
3.Tash 32, the rest 0, no runs, thus: to mark a 0
4.Tash 16, the rest 0, no runs, thus: to mark a 0
5.Tash 8, the rest 0, no runs, thus: to mark a 0
6.Tash 4, the rest 0, no runs, thus: to mark a 0
7.Tash 2, the rest 0, no runs, thus: to mark a 0
8.Tash 1, the rest 0, no runs, thus: to mark a 0
From this conclude that the first octet is converted into 192 bits gives us this:
11000000, ie the first octet is 8 bits (after ip has 4 octets of 8 bits 32 bits total)
--------------------------------
Second octet is below 168 now denote by
128, 64, 32, 16, 8, 4, 2, 1
Octet is DYT (168)
1.Tash 128 to 168, goes to her and mark a 1 1 (168-128 = 40) ie residue 40
2.Tash 64 does not go to 40 (remainder of 168-128) and remark the 0
3.Tash 32 runs, her first in 40 (remainder of 168-128) and remark the 1 (40-32 = 8) residue ie 8
4.Tash 16 does not go to 8 (40-32 = 8) and remark the 0
5.Tash 8 runs, 1 times for 8 (residue from 0-32 = 8) and remark the 1 (8-8 = 0) ie remainder 0
6.Tash 4, the rest 0, no runs, thus: to mark a 0
7.Tash 2, the rest 0, no runs, thus: to mark a 0
8.Tash 1, the rest 0, no runs, thus: to mark a 0
From this conclude that the second octet is converted into 168 bits gives us this:
10101000
--------------------------------
The third octet is now 24 below mark with
128, 64, 32, 16, 8, 4, 2, 1
THREE octet (24)
1.Tash 128, at 24, does not go, thus: to mark a 0
2.Tash 64, at 24, does not go, thus: to mark a 0
3.Tash 32, at 24, does not go, thus: to mark a 0
4.Tash 16, at 24, goes 1her Internet, so that mark a 1, (24-16 = 8) residue ie 8
5.Tash 8, at 8 (remainder of 24-16 = 8), runs 1her Internet, so that mark a 1, (8-8 = 0) ie remainder 0
6.Tash 4, the rest 0, no runs, thus: to mark a 0
7.Tash 2, the rest 0, no runs, thus: to mark a 0
8.Tash 1, the rest 0, no runs, thus: to mark a 0
From this conclude that the third octet is converted into 24 bits gives us this:
00011000
--------------------------------
The fourth octet is 8 now denote with down
128, 64, 32, 16, 8, 4, 2, 1
FOURTH octet (8)
1.Tash 128, 8, no runs, thus: to mark a 0
2.Tash 64, 8, no runs, thus: to mark a 0
3.Tash 32, 8, no runs, thus: to mark a 0
4.Tash 16, 8, no runs, thus: to mark a 0
5.Tash 8, 8, goes 1her Internet, so that mark a 1, (8-9 = 0) ie remainder 0
6.Tash 4, the rest 0, no runs, thus: to mark a 0
7.Tash 2, the rest 0, no runs, thus: to mark a 0
8.Tash 1, the rest 0, no runs, thus: to mark a 0
From this conclude that the fourth octet is converted into 8 bits gives us this:
00001000
--------------------------------
Ie we converted the 4 octet one by one:
192:11000000
168:10101000
24:00011000
8:00001000
Tanii conclude that the ip 192.168.24.8 bits of konertojm we obtain this value:
11000000 10101000 00011000 00001000
So: 192.168.24.8 = 11000000 10101000 00011000 00001000
I hope you kuptur this tutorial, since that is really very important since all communication is done in this way, meaning each communication is the NAZ.
Ie when there is then a signal, and when no signal is 0
originag tutorial in albanian
Konvertimi i IP-s ne bita
Përshëndetje .
Në kët tutorial do tju tregoj se ti ta konvertojme 1 ip , ne bita .
Siq e dim IP Verssion 4 , qe perdorim ne eshte 32 bitsh , pasi perbehet nga 4 oktete me nga 8 bita , 8 x 4 = 32 bita .
Le të vazhdojmë me tutorialin , e marrim 1 IP , përshembull 192.168.24.8 , tash do te fillojme me konvertimin ne bita .
Okteti i parë 192 tash shënojmë me posht
128 , 64 , 32 , 16 , 8 , 4 , 2 , 1
--------------------------------
OKTETI I PARE ( 192 )
1.Tash 128 në 192 , shkon 1 her dhe shenojm 1 (192-128=64) dmth mbetja 64
2.Tash 64 shkon 1 her ne 64 (Mbetja nga 192-168) dhe shenojme 1 , tash 64-64= 0 , dmth mbetja 0
3.Tash 32 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
4.Tash 16 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
5.Tash 8 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
6.Tash 4 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
7.Tash 2 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
8.Tash 1 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
Nga kjo perfundojm se kur okteti i pare 192 shendrrohet ne bita na jep ket :
11000000 , dmth okteti i pare i ka 8 bita ( pasi ip i ka 4 oktete nga 8 bita gjithsej 32 bita)
--------------------------------
Okteti i dytë 168 tash shënojmë me posht
128 , 64 , 32 , 16 , 8 , 4 , 2 , 1
OKTETI I DYT (168)
1.Tash 128 në 168 , shkon 1 her dhe shenojm 1 (168-128=40) dmth mbetja 40
2.Tash 64 nuk shkon ne 40 (Mbetja nga 168-128) dhe shenojme 0
3.Tash 32 shkon , 1 her ne 40 (Mbetja nga 168-128) dhe shenojme 1 (40-32=8) dmth mbetja 8
4.Tash 16 nuk shkon ne 8 (40-32=8) dhe shenojme 0
5.Tash 8 shkon , 1 her ne 8 (Mbetja nga 0-32=8) dhe shenojme 1 (8-8=0) dmth mbetja 0
6.Tash 4 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
7.Tash 2 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
8.Tash 1 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
Nga kjo perfundojm se kur okteti i dyte 168 shendrrohet ne bita na jep ket :
10101000
--------------------------------
Okteti i trete 24 tash shënojmë me posht
128 , 64 , 32 , 16 , 8 , 4 , 2 , 1
OKTETI I TRETE (24)
1.Tash 128 , ne 24 , nuk shkon , kshtu qe shenojm 0
2.Tash 64 , ne 24 , nuk shkon , kshtu qe shenojm 0
3.Tash 32 , ne 24 , nuk shkon , kshtu qe shenojm 0
4.Tash 16 , ne 24 , shkon 1her , kshtu qe shenojm 1 , (24-16=8) dmth mbetja 8
5.Tash 8 , ne 8 (Mbetja nga 24-16=8) , shkon 1her , kshtu qe shenojm 1 , (8-8=0) dmth mbetja 0
6.Tash 4 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
7.Tash 2 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
8.Tash 1 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
Nga kjo perfundojm se kur okteti i trete 24 shendrrohet ne bita na jep ket :
00011000
--------------------------------
Okteti i katert 8 tash shënojmë me posht
128 , 64 , 32 , 16 , 8 , 4 , 2 , 1
OKTETI I KATERT (8)
1.Tash 128 , ne 8 , nuk shkon , kshtu qe shenojm 0
2.Tash 64 , ne 8 , nuk shkon , kshtu qe shenojm 0
3.Tash 32 , ne 8 , nuk shkon , kshtu qe shenojm 0
4.Tash 16 , ne 8 , nuk shkon , kshtu qe shenojm 0
5.Tash 8 , ne 8 , shkon 1her , kshtu qe shenojm 1 , (8-9=0) dmth mbetja 0
6.Tash 4 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
7.Tash 2 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
8.Tash 1 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
Nga kjo perfundojm se kur okteti i katert 8 shendrrohet ne bita na jep ket :
00001000
--------------------------------
Dmth i kemi konvertuar te 4 Oktet nje nga nje :
192:11000000
168:10101000
24:00011000
8:00001000
Tanii arrijm ne perfundimin se kur ip 192.168.24.8 e konertojm ne bita fitojm ket vler :
11000000 10101000 00011000 00001000
Pra : 192.168.24.8 = 11000000 10101000 00011000 00001000
Shpresoj qe ta keni kuptur ket tutorial , pasi qe eshte me te vertet shum i rendesishem pasi i gjith komunikimi behet ne ket menyr , dmth eshte naz e cdo komunikimi.
Dmth kur esht 1 ateher ka sinjal , kurse kur eshte 0 nuk ka sinjal
Greetings.
In this tutorial will tell you that you to convert an ip, in bits.
As the dim IP Verssion 4, we use is 32 bitsh, as consists of 4 octets with 8 bits, 8 x 4 = 32 bits.
Let's continue with the tutorial, we get 1 IP, 192.168.24.8 for example, will now start with converting the bits.
First octet is below 192 now denote by
128, 64, 32, 16, 8, 4, 2, 1
--------------------------------
FIRST octet (192)
1.Tash 128 to 192, goes to her and mark a 1 1 (192-128 = 64) ie residue 64
2.Tash 64 runs in her first 64 (remainder of 192-168) and remark the one, now 64-64 = 0, ie remaining 0
3.Tash 32, the rest 0, no runs, thus: to mark a 0
4.Tash 16, the rest 0, no runs, thus: to mark a 0
5.Tash 8, the rest 0, no runs, thus: to mark a 0
6.Tash 4, the rest 0, no runs, thus: to mark a 0
7.Tash 2, the rest 0, no runs, thus: to mark a 0
8.Tash 1, the rest 0, no runs, thus: to mark a 0
From this conclude that the first octet is converted into 192 bits gives us this:
11000000, ie the first octet is 8 bits (after ip has 4 octets of 8 bits 32 bits total)
--------------------------------
Second octet is below 168 now denote by
128, 64, 32, 16, 8, 4, 2, 1
Octet is DYT (168)
1.Tash 128 to 168, goes to her and mark a 1 1 (168-128 = 40) ie residue 40
2.Tash 64 does not go to 40 (remainder of 168-128) and remark the 0
3.Tash 32 runs, her first in 40 (remainder of 168-128) and remark the 1 (40-32 = 8) residue ie 8
4.Tash 16 does not go to 8 (40-32 = 8) and remark the 0
5.Tash 8 runs, 1 times for 8 (residue from 0-32 = 8) and remark the 1 (8-8 = 0) ie remainder 0
6.Tash 4, the rest 0, no runs, thus: to mark a 0
7.Tash 2, the rest 0, no runs, thus: to mark a 0
8.Tash 1, the rest 0, no runs, thus: to mark a 0
From this conclude that the second octet is converted into 168 bits gives us this:
10101000
--------------------------------
The third octet is now 24 below mark with
128, 64, 32, 16, 8, 4, 2, 1
THREE octet (24)
1.Tash 128, at 24, does not go, thus: to mark a 0
2.Tash 64, at 24, does not go, thus: to mark a 0
3.Tash 32, at 24, does not go, thus: to mark a 0
4.Tash 16, at 24, goes 1her Internet, so that mark a 1, (24-16 = 8) residue ie 8
5.Tash 8, at 8 (remainder of 24-16 = 8), runs 1her Internet, so that mark a 1, (8-8 = 0) ie remainder 0
6.Tash 4, the rest 0, no runs, thus: to mark a 0
7.Tash 2, the rest 0, no runs, thus: to mark a 0
8.Tash 1, the rest 0, no runs, thus: to mark a 0
From this conclude that the third octet is converted into 24 bits gives us this:
00011000
--------------------------------
The fourth octet is 8 now denote with down
128, 64, 32, 16, 8, 4, 2, 1
FOURTH octet (8)
1.Tash 128, 8, no runs, thus: to mark a 0
2.Tash 64, 8, no runs, thus: to mark a 0
3.Tash 32, 8, no runs, thus: to mark a 0
4.Tash 16, 8, no runs, thus: to mark a 0
5.Tash 8, 8, goes 1her Internet, so that mark a 1, (8-9 = 0) ie remainder 0
6.Tash 4, the rest 0, no runs, thus: to mark a 0
7.Tash 2, the rest 0, no runs, thus: to mark a 0
8.Tash 1, the rest 0, no runs, thus: to mark a 0
From this conclude that the fourth octet is converted into 8 bits gives us this:
00001000
--------------------------------
Ie we converted the 4 octet one by one:
192:11000000
168:10101000
24:00011000
8:00001000
Tanii conclude that the ip 192.168.24.8 bits of konertojm we obtain this value:
11000000 10101000 00011000 00001000
So: 192.168.24.8 = 11000000 10101000 00011000 00001000
I hope you kuptur this tutorial, since that is really very important since all communication is done in this way, meaning each communication is the NAZ.
Ie when there is then a signal, and when no signal is 0
originag tutorial in albanian
Konvertimi i IP-s ne bita
Përshëndetje .
Në kët tutorial do tju tregoj se ti ta konvertojme 1 ip , ne bita .
Siq e dim IP Verssion 4 , qe perdorim ne eshte 32 bitsh , pasi perbehet nga 4 oktete me nga 8 bita , 8 x 4 = 32 bita .
Le të vazhdojmë me tutorialin , e marrim 1 IP , përshembull 192.168.24.8 , tash do te fillojme me konvertimin ne bita .
Okteti i parë 192 tash shënojmë me posht
128 , 64 , 32 , 16 , 8 , 4 , 2 , 1
--------------------------------
OKTETI I PARE ( 192 )
1.Tash 128 në 192 , shkon 1 her dhe shenojm 1 (192-128=64) dmth mbetja 64
2.Tash 64 shkon 1 her ne 64 (Mbetja nga 192-168) dhe shenojme 1 , tash 64-64= 0 , dmth mbetja 0
3.Tash 32 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
4.Tash 16 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
5.Tash 8 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
6.Tash 4 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
7.Tash 2 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
8.Tash 1 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
Nga kjo perfundojm se kur okteti i pare 192 shendrrohet ne bita na jep ket :
11000000 , dmth okteti i pare i ka 8 bita ( pasi ip i ka 4 oktete nga 8 bita gjithsej 32 bita)
--------------------------------
Okteti i dytë 168 tash shënojmë me posht
128 , 64 , 32 , 16 , 8 , 4 , 2 , 1
OKTETI I DYT (168)
1.Tash 128 në 168 , shkon 1 her dhe shenojm 1 (168-128=40) dmth mbetja 40
2.Tash 64 nuk shkon ne 40 (Mbetja nga 168-128) dhe shenojme 0
3.Tash 32 shkon , 1 her ne 40 (Mbetja nga 168-128) dhe shenojme 1 (40-32=8) dmth mbetja 8
4.Tash 16 nuk shkon ne 8 (40-32=8) dhe shenojme 0
5.Tash 8 shkon , 1 her ne 8 (Mbetja nga 0-32=8) dhe shenojme 1 (8-8=0) dmth mbetja 0
6.Tash 4 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
7.Tash 2 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
8.Tash 1 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
Nga kjo perfundojm se kur okteti i dyte 168 shendrrohet ne bita na jep ket :
10101000
--------------------------------
Okteti i trete 24 tash shënojmë me posht
128 , 64 , 32 , 16 , 8 , 4 , 2 , 1
OKTETI I TRETE (24)
1.Tash 128 , ne 24 , nuk shkon , kshtu qe shenojm 0
2.Tash 64 , ne 24 , nuk shkon , kshtu qe shenojm 0
3.Tash 32 , ne 24 , nuk shkon , kshtu qe shenojm 0
4.Tash 16 , ne 24 , shkon 1her , kshtu qe shenojm 1 , (24-16=8) dmth mbetja 8
5.Tash 8 , ne 8 (Mbetja nga 24-16=8) , shkon 1her , kshtu qe shenojm 1 , (8-8=0) dmth mbetja 0
6.Tash 4 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
7.Tash 2 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
8.Tash 1 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
Nga kjo perfundojm se kur okteti i trete 24 shendrrohet ne bita na jep ket :
00011000
--------------------------------
Okteti i katert 8 tash shënojmë me posht
128 , 64 , 32 , 16 , 8 , 4 , 2 , 1
OKTETI I KATERT (8)
1.Tash 128 , ne 8 , nuk shkon , kshtu qe shenojm 0
2.Tash 64 , ne 8 , nuk shkon , kshtu qe shenojm 0
3.Tash 32 , ne 8 , nuk shkon , kshtu qe shenojm 0
4.Tash 16 , ne 8 , nuk shkon , kshtu qe shenojm 0
5.Tash 8 , ne 8 , shkon 1her , kshtu qe shenojm 1 , (8-9=0) dmth mbetja 0
6.Tash 4 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
7.Tash 2 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
8.Tash 1 , ne mbetjen 0 , nuk shkon , kshtu qe shenojm 0
Nga kjo perfundojm se kur okteti i katert 8 shendrrohet ne bita na jep ket :
00001000
--------------------------------
Dmth i kemi konvertuar te 4 Oktet nje nga nje :
192:11000000
168:10101000
24:00011000
8:00001000
Tanii arrijm ne perfundimin se kur ip 192.168.24.8 e konertojm ne bita fitojm ket vler :
11000000 10101000 00011000 00001000
Pra : 192.168.24.8 = 11000000 10101000 00011000 00001000
Shpresoj qe ta keni kuptur ket tutorial , pasi qe eshte me te vertet shum i rendesishem pasi i gjith komunikimi behet ne ket menyr , dmth eshte naz e cdo komunikimi.
Dmth kur esht 1 ateher ka sinjal , kurse kur eshte 0 nuk ka sinjal
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